Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The work done in blowing a soap bubble of 10 cm radius is (Surface tension of the soap solution is $\frac{3}{100} \mathrm{N/m}$ )
Text Solution
Verified by ExpertsThe correct answer is:
A
Work done $U = W = 8 \pi R^{2} t$ ,
Here
$R = 10 \times 10^{-2} \text{ m and}$ $T = (3/100) \text{ N/m}$ $W = 8 \pi \times (10 \times 10^{-2})^2 \times (3/100)$ $= 75.36 \times 10^{-4} \text{ J}$
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